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Micah needs to solve the inequality n−16≤4n−5.

His work follows.

n−16≤4n−5

Step A: −3n−16≥−5

Step B: −3n≥11

Step C: n≤−113

At which step, if any, did Micah make a mistake?

1 Answer

5 votes
Step A
There was no need to flip the sign when subtracting 4n from each side
User Nasi
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