Question

a ballon has a volume of 253.2 mL. the volume of the balloon is decreased to 165.4 mL determine new tempature

Answer 1

if pressure is constant ...

and initial temperature is 273 K then,

V1 / T1 = V2 / T2

253.2 / 273 = 165.4 / T2

T2 = 178.33 K

Answer 2

The question is incomplete. Here, is the complete question:

A balloon has a volume of 253.2 mL at 356 K. The volume of the balloon is decreased to 165.4 mL. What is the new temperature?

Answer: The new temperature is 232.6 K.

Step-by-step explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

`V\propto T` (At constant pressure and number of moles)

`(V_1)/(T_1)=(V_2)/(T_2)`

where,

`V_1` = initial volume of gas = 253.2 ml

`V_2` = final volume of gas = 165.4 ml

`T_1` = initial temperature of gas= 356 K

`T_2` = final temperature of gas = ?

Putting in the values:

`(253.2)/(356)=(165.4)/(T_2)`

`T_2=232.6K`

Therefore, the new temperature is 232.6 K.