Question

Philip is having a party and wants to spend less than $588. He has already spent $500. The only item left on his list is sodas, which cost $8 per case. How many cases of soda, x, can Philip purchase and stay under his budget? Select the number line that includes the largest number of cases of soda that Philip can purchase and still stay under his budget.

A.

6 7 8 9 10 11 12 13 14 15 16 17 18


B.

7 8 9 10 11 12 13 14 15 16 17 18 19


C.

6 7 8 9 10 11 12 13 14 15 16 17 18


D.

7 8 9 10 11 12 13 14 15 16 17 18 19

Answer 1

Philip can buy a maximum of 11 cases of soda with the remaining $88 from his budget, with each case costing $8. The correct number line is Option A, which includes the number 11.

Step-by-step explanation:

Philip wants to stay under a budget of $588 and has already spent $500. With each case of sodas costing $8, we need to determine how many cases, x, he can purchase without exceeding his budget. We start by finding the remaining amount Philip can spend, which is $588 - $500 = $88.

Next, we determine the maximum number of soda cases he could buy by dividing the remaining budget by the cost per case: $88 / $8 per case = 11 cases.

Thus, the largest number of cases Philip can buy without exceeding his budget is 11. Therefore, the correct number line that includes the largest number of cases of soda Philip can purchase while staying under his budget is Option A, which ends with the number 11.

Answer 2

The following expression can be written from the data

588-500/8=x
88/8=x
11=x
Phillip can buy 11 cans of soda exactly to meet his budget. To stay under his budget he would need to buy less than that so the number line would look like this.

x<11