Final answer:
To find the equilibrium partial pressure of SO2, subtract the vapor pressure of water at 298 K from the total pressure and divide by two. The vapor pressure of water is given as 23 torr, but we lack the total pressure to perform the calculation.
Step-by-step explanation:
To calculate the equilibrium partial pressure of SO2 in the system at 298 K, assuming the partial pressure is equal to that of H2S and that the system includes the vapor pressure of water, we need to use Dalton's Law of Partial Pressures. The total pressure in the system is the sum of the partial pressures of the individual gases. However, the provided vapor pressure of water is at a different temperature than required (22°C instead of the 298 K, which is approximately 25°C).
We can use an equation from the given information:
Ptotal - PH2O = PSO2 + PH2S
Given that PSO2 = PH2S, we can simplify the expression as:
2PSO2 = Ptotal - PH2O
Thus, to find the equilibrium partial pressure of SO2, we would take the total pressure, subtract the vapor pressure of water at 298 K, and divide by two. The vapor pressure of water at 25°C (298 K) is typically around 23.76 torr, but the student provided the vapor pressure as 23 torr, which we'll use for this calculation.
PSO2 = (Ptotal - 23 torr) / 2
To give a numerical answer, the total pressure of the system would need to be provided. Without that information, we cannot calculate the exact value for PSO2.