Question

Questions 1. What conclusions can you draw about the results of your first cross, between a homozygous red bull (RR) and a heterozygous red cow (Rr)? Answer:

2. What conclusions can you draw about the results of your second cross, between a heterozygous red bull (Rr) and a heterozygous red cow (Rr)? Answer:


3. What conclusions can you draw about the results of your third cross, between a homozygous white bull (rr) and a homozygous white cow (rr)?

Answer 1

Answer:a)Therefore:Crossing results in 50% (dominant homozygote) and 50% (dominant heterozygote).b)Therefore:Crossing results in 25% (dominant homozygote), 50% (dominant heterozygote) and 25% (homozygous recessive).c)Therefore:Crossing results in 100% (homozygous recessive).

Explanation:i did nothing

Answer 2

a)


`RR\:x\:Rr`

`\underbrace{RR\:x\:Rr}`

`RR, Rr, RR, Rr`

`\underbrace{RR,RR}_(50\%),\underbrace{Rr,Rr}_(50\%)`

Therefore:
Crossing results in 50% (dominant homozygote) and 50% (dominant heterozygote).

b)


`Rr\:x\:Rr`

`\underbrace{Rr\:x\:Rr}`

`RR, Rr, Rr, rr`

`\underbrace{RR}_(25\%),\underbrace{Rr,Rr}_(50\%), \underbrace{rr}_(25\%)`

Therefore:
Crossing results in 25% (dominant homozygote), 50% (dominant heterozygote) and 25% (homozygous recessive).

c)


`rr\:x\:rr`

`\underbrace{rr\:x\:rr}`

`rr, rr, rr, rr`

`\underbrace{rr,rr,rr,rr}_(100\%)`

Therefore:
Crossing results in 100% (homozygous recessive).