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Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly. Without looking, Allen draws one letter. Expressed as a fraction, decimal, and percentage, what is the probability that Allen will NOT select a consonant?

User NickDelta
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2 Answers

2 votes
im pritty sure it would be 30%

User Stephen Harris
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7 votes

Answer:
\text{P(Not consonant)}=(3)/(8)

In decimal,
0.375

In percentage,
37.5\%

Explanation:

Given: Christopher mixes the letters S, E, L, E, C, T, E, and D thoroughly.

Total number of letters= 8

The number of consonant=5 (S, L, C, T, D )

The number of letters which are not consonants (vowels)=8-5=3

Now, the probability that Allen will NOT select a consonant is given by :-


\text{P(Not consonant)}=\frac{\text{number of non consonant letters}}{\text{total letters}}


\\\Rightarrow\ \text{P(Not consonant)}=(3)/(8)

In decimal,
(3)/(8)=0.375

In percentage,
(3)/(8)*100=37.5\%

User Matt Dowle
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7.1k points