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2 votes
Justify 2.010010001.....is an irrational number

User PJay
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2 Answers

4 votes
no its rational....................

User Rolevax
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A decimal expansion of a rational number either terminates or follows a repeating pattern of a *finite* sequence of digits.

Neither of these is the case here. The decimal expansion is obviously non-terminating, nor is the sequence of digits finite.

Writing the number as


2.010010001\ldots=1+1.010010001\ldots

and only considering the second number, you have the following sequence of digits:
\{1,0,1,0,0,1,0,0,0,1,\ldots\}, where the
nth term, starting with
n=0 corresponds to the number
10^(-n). The sequence can be described recursively by the recurrence


\begin{cases}a_0=1\\a_(n+1)=a_n+n+2&\text{for }n\ge1\end{cases}

and explicitly by
a_n=\frac{n(n+3)}2.

This sequence is not periodic, and indeed diverges to
\infty as
n\to\infty. This means the number cannot be rational.
User Madesch
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