What are the solutions to the quadratic equation x^2-15x+36=0

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asked Dec 28, 2018 116k views

1 Answer

Nucleon · Answer 1 · 2019-01-01T10:09:46+0000

x² - 15 x + 36 = 0
x² - 12x - 3x + 36 = 0
x( x - 12) - 3( x - 12) = 0
(x - 3)( x - 12) = 0

x - 3 = 0
x = 3
or
x - 12 = 0
x = 12

The solutions are 3 and 12

What are the solutions to the quadratic equation x^2-15x+36=0

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