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If 35.8 grams of LiCl are dissolved in 184 grams of water, what is the concentration of the solution in percent by mass?

2 Answers

4 votes
mass of solute = 35.8 g

mass of solvent = 184 g

w ( % ) = 35.8 / 35.8 + 184

w ( % ) = 35.8 / 219.8

= 0.1628 x 100 => 16.28 %
User Blandaadrian
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7 votes

Answer : The concentration of solution in percent by mass is 16.3 %

Explanation :

Percent by mass : It means that the mass of solute present in the mixture and multiply by 100.

Given:

Mass of LiCl = 35.8 g

Mass of water = 184 g

First we have to calculate the mass of mixture.

Mass of mixture = Mass of LiCl + Mass of water

Mass of mixture = 35.8 g + 184 g

Mass of mixture = 219.8 g

Now we have to calculate the concentration of solution in percent by mass.


\text{Concentration of solution in percent by mass}=\frac{\text{Mass of }LiCl}{\text{Mass of mixture}}* 100


\text{Concentration of solution in percent by mass}=(35.8g)/(219.8g)* 100=16.3\%

Therefore, the concentration of solution in percent by mass is 16.3 %

User Dhrumil Bhankhar
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