Question

On a winter day a child of mass 20.0 kg slides on a horizontal sidewalk covered in ice. Initially she is moving at 3.00 m>s, but due to friction she comes to a halt in 2.25 m. What is the magnitude of the constant friction force that acts on her as she slides

Answer 1

40 N

Step-by-step explanation:

According to the scenario, computation of given data are as follows:

Mass (m) = 20 kg

Initially moving (v) = 3

Actual distance (d) = 2.25 m

So, we can calculate friction (f) by using following formula,

f × d =
`(1)/(2) mv^(2)`

By putting the value, we get

f × 2.25 =
`(1)/(2)` × 20 ×
`3^(2)`

f × 2.25 = 10 × 9

f = 90 ÷ 2.25

= 40 N.