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Find the volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm.

User Arkade
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The volume of a square pyramid with base edges of 48 cm and a slant height of 26 cm = 7,680cm^3
User Mubeen Ali
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Answer:
\text{V}=7,680\ cm^3

Explanation:

The volume of a pyramid is given by :-


\text{Volume}=(1)/(3)\text{base area *height}

Given: Slant height of the pyramid (l)= 26 cm

The base edge of the pyramid (s)=48 cm

Now, the height of the pyramid is given by :


h=\sqrt{l^2-((s)/(2))^2}\\\\\Rightarrow\ h=\sqrt{26^2-((48)/(2))^2}\\\\\Rightarrow\ h=10\ cm

Now, the volume of the square pyramid is given by :-


\text{V}=(1)/(3)(48)^2(10)\\\\\Rightarrow\ \text{V}=7680\ cm^3

User The Machine
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