Question

Solve x^2 + 6x + 4=0?

Answer 1

You need to use the quadratic formula for this question.

`(-b+- √(b^2-4ac) )/(2a)`
In your equation, a is 1, b is 6, and c is 4. (I couldn't find a plus minus sign, so that's what the +- means, sorry if there's confusion.)
Sub those into the quadratic formula, and

`(-6+- √((6)^2-4(1)(4)) )/(2(1))`
For the first answer, we should get
x1=-0.7639, when you add the √6^2-4(1)(4)
For the second answer, we get
x2=-5.2361 when we subtract the √6^2-4(1)(4)
Therefore, the x values that make this equation equal to 0 should be approximately -0.7639 and -5.2361.
The more specific answers are
x1= -3+√5 and x2=-3-√5.