Question

The value of gravitational acceleration of a body on Earth is 9.8 meters/second2. The gravitational potential energy for a 1.00 kilogram object is found to be 12.5 joules. How high is this object above the ground level, where PE = 0?

Answer 1

its A 2.3

Step-by-step explanation:

you have to simplify!

Answer 2

Answer: 1.28 m

Step-by-step explanation:

the gravitational potential energy of an object is given by

`E=mgh`

where

m is the mass of the object

g is the gravitational acceleration

h is the height of the object with respect to a reference point.

In this problem, m=1.00 kg, g=9.8 m/s^2, and the energy of the object measured with respect to the ground level is E=12.5 J. Therefore, by re-arranging the equation we can calculate h, the height of the object above the ground level:

`h=(E)/(mg)=(12.5 J)/((1.00 kg)(9.8 m/s^2))=1.28 m`