Question

A hockey puck slides to a stop on ice. The coefficient of friction between the puck and

the ice is 0.026. What is the puck’s acceleration?

Answer 1

The acceleration of the puck can be determined using Newton's second law of motion. The formula for the acceleration is (coefficient of friction) * (acceleration due to gravity). Therefore, the puck's acceleration is approximately 0.2548 m/s^2.

Step-by-step explanation:

The acceleration of the puck can be determined using Newton's second law of motion, which states that the net force acting on an object is equal to the product of its mass and acceleration.

The net force in this case is the force of kinetic friction, which is given by the coefficient of friction multiplied by the normal force. Since the puck is on a horizontal surface, the normal force is equal to the weight of the puck.

Therefore, the formula for the acceleration is:

acceleration = (coefficient of friction) * (acceleration due to gravity)

Plugging in the values, we get:

acceleration = 0.026 * 9.8 m/s^2 = 0.2548 m/s^2

So, the puck's acceleration is approximately 0.2548 m/s^2.

Answer 2

Step-by-step explanation:

The puck slides on the ice . Coefficient of sliding friction μ = .026

Limiting frictional force = μ R

R is reaction force of the surface .

R = mg

Friction force = μ mg

deceleration = μ mg / m

= μ g

= .026 x 9.8 = .2548

= 0.26 m /s².