Answer with explanation:
Perimeter of watermelon field
yard
1 yard =3 feet
So, perimeter
feet
Width of Watermelon field = 44 feet
Kaisa , plants watermelon in the field in rows which are
feet apart.
Number of watermelon planted in a single row =x
Let , Length of Watermelon field

Perimeter of field = 2 *[Length +Breadth]
![214=2*[44+(8(x-1))/(3)]\\\\(214)/(2)=44+(8(x-1))/(3)\\\\107-44=(8(x-1))/(3)\\\\63=(8(x-1))/(3)\\\\x-1=(3*63)/(8)\\\\x=(189)/(8)+1\\\\x=(197)/(8)\\\\x=24(5)/(8)](https://img.qammunity.org/2018/formulas/mathematics/middle-school/1eol32925rs7n84rdlotjvy1u0k7evfsak.png)
Number of watermelon in a row =24(approx)
Length of watermelon field
feet
Let number of rows of watermelon = y

= 2 Rows(approximately)