Question

Suppose a granola bar company estimates that its monthly cost isC(a) = 5000 + 400m and its monthly revenue isR(a) = -0,68 + 800w- 3000 + 600, where x is in thousands ofgranola bars sold. The profit is the difference between the revenue and thecostWhat is the profit function, P(x)?A P(a) = 0,6m9 – 3002° + 7000 - 600O B. P(m) = 0.629 + 300m? – 7000 + 600C, P(w) = -0,68 + 300m? – 700x + 600D. P(a) = -0.6m + 1300+100% + 600SUBMIT

Answer 1

R(a) = -0,68 + 800w- 3000 + 600, where x

P(x) = R(x) - C(x)

Then find

(800- 500)x^2 = 300x^2

(-300 - 400)x= -700x

-0.6x^3 dont change

600 dont change

Then answer is OPTION C)

-0.6X^3 + 300X^2 - 700X + 600