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8 votes
8 votes
A tire swing hangs straight down. Then a child gets on, swings forward 50°, and swings back 95°. How many degrees forward must the swing go to return to its starting position?

User Govind Prajapati
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1 Answer

14 votes
14 votes

Let's draw a picture of the problem:

From the picture above, we can see that the difference (x) between the second and third position is


95-50=x

which gives


x=45

How many degrees forward must the swing go to return to its starting position? ​Answer: 45 degrees forward

A tire swing hangs straight down. Then a child gets on, swings forward 50°, and swings-example-1
User Shrys
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