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The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypotenuse is (??) units, and the area of the triangle …
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The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypotenuse is (??) units, and the area of the triangle …
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Feb 5, 2018
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The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypotenuse is (??) units, and the area of the triangle is (??) square units. (Hint: Use the Pythagorean theorem.)
Mathematics
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Cantdutchthis
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A=1/2 b times h
1/2(3 times 4)
=6 is the correct answer
AquilaX
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Feb 7, 2018
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Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5
then find area
A=1/2bh
1/2(3*4)
6
Jcoppens
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Feb 9, 2018
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