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The three vertices of a triangle drawn on a complex plane are represented by 0 + 0i, 4 + 0i, and 0+ 3i. The length of the hypotenuse is (??) units, and the area of the triangle is (??) square units. (Hint: Use the Pythagorean theorem.)

2 Answers

2 votes
A=1/2 b times h
1/2(3 times 4)
=6 is the correct answer

User AquilaX
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4 votes
Once you have the points they make a 3-4-5 triangle. The two legs are 3 and 4, so the hypotenuse has to be 5. Or you could use the pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5
then find area
A=1/2bh
1/2(3*4)
6
User Jcoppens
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7.7k points