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29 votes
29 votes
Can you please help me out with a question

User Liam Potter
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1 Answer

21 votes
21 votes

P(\text{Event)}=\frac{n\text{ (Event)}}{Total\text{ Event}}
P(\text{outer most ring)=}\frac{area\text{ of the outer most ring}}{area\text{ of the dartboard}}
\begin{gathered} Area\text{ of the dartboard=}\pi* R^2 \\ Where\text{ R=6} \\ \text{Area of the dartboard=}\pi*6^2 \\ \text{Area of the dartboard=}36\pi \end{gathered}
\begin{gathered} \text{Area of the outermost ring=Area of the dartboard - Area of the inner ring} \\ \text{Area of the outermost ring=36}\pi-(\pi*4^2)=36\pi-16\pi=20\pi \end{gathered}
\begin{gathered} P(\text{outermost ring)=}(20\pi)/(36\pi) \\ P(\text{outermost ring)=}(5)/(9) \end{gathered}

The probability of the outermost ring is 55.6%

User Jonyjm
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