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7 votes
3 math questions multiple choice

User Eugene Yu
by
2.1k points

1 Answer

25 votes
25 votes

1) the equation is:


2y+x=4

So we can rewrite the equation as a slope intercept so:


\begin{gathered} 2y=-x+4 \\ y=-(1)/(2)x+2 \end{gathered}

So the slope is -1/2

2) the equation is:


3x-2y=5

Now we evaluete the coordinates to see which one is not on the line so for (1,-1)


\begin{gathered} 3(1)-2(-1)=5 \\ 3+2=5 \\ 5=5 \end{gathered}

So is on the line

for (-1,-4)


\begin{gathered} 3(-1)-2(-4)=5 \\ -3+8=5 \\ 5=5 \end{gathered}

So it is on the line

for (3,2)


\begin{gathered} 3(3)-2(2)=5 \\ 9-4=5 \\ 5=5 \end{gathered}

So it is on the line

Finally for (1,2)


\begin{gathered} 3(1)-2(2)=5 \\ 3-4=5 \\ -1\\e5 \end{gathered}

So (1,2) is not on the line

3) if the slope is -2 and goes to the point (3,-1) we can use the equation of a line to find the intercept so:


\begin{gathered} y=-2x+b \\ -1=-2(3)+b \\ -1=-6+b \\ -1+6=b \\ 5=b \end{gathered}

So the intercept is 5 so the equation is:


y=-2x+5

User Ashu Grover
by
2.9k points
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