Question

What is the speed at the bottom of the funnel?

Answer 1

We will have the following:

`\begin{cases}I=r^2m \\ \\ L=I\omega \\ \\ \omega=v/r\end{cases}`

So:

We will find the data we can with the given information:

`\omega_1=(0.3m/s)/(0.2m)\Rightarrow\omega=(1.5)/(s)`

Also:

`I\omega_1=I\omega_2\Rightarrow\omega_1=\omega_2`

So:

`(1.5)/(s)=(v)/(0.03m)\Rightarrow v=0.045m/s`

So, the velocity at the bottom of the funnel is 0.045m/s.