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A parabola-shaped hill can be modeled by equation

y=-2(x - 3)2 +6, where x and y are measured in
kilometers.
How wide is the bottom of the hill? Assume the r -axis is
ground level. Round to the nearest tenths.
kilometers

User Erikcw
by
8.1k points

1 Answer

12 votes

Answer:3.46 km

Explanation:

Given

shape of hill
y=-2(x-3)^2+6

at the bottom y=0 i.e.


0=-2(x-3)^2+6\\(x-3)^2=3\\x-3=\pm√(3)\\x=3\pm√(3)

width of the bottom


3+√(3)-[3-√(3)]=2√(3)\ km\ or\ 3.46\ km

User Kaydi
by
8.2k points

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