Question

A parabola-shaped hill can be modeled by equation

y=-2(x - 3)2 +6, where x and y are measured in
kilometers.
How wide is the bottom of the hill? Assume the r -axis is
ground level. Round to the nearest tenths.
kilometers

Answer 1

Answer:3.46 km

Explanation:

Given

shape of hill
`y=-2(x-3)^2+6`

at the bottom y=0 i.e.

`0=-2(x-3)^2+6\\(x-3)^2=3\\x-3=\pm√(3)\\x=3\pm√(3)`

width of the bottom

`3+√(3)-[3-√(3)]=2√(3)\ km\ or\ 3.46\ km`