Question

2. An object is moving in the positive x-direction while a net force directed along the x-axis is exerted on

the object. The figure shows the force as a function of position. What is the net work done on the object
over the distance shown?
F
FO
o
2d
3d
-Fof
A) Fid
B) Ford
C) 2Fd
D) 4F,

Answer 1

A. F₀d

Step-by-step explanation:

The formula for work done on an object is given by:

w= f*d

Work done towards the positive direction is given by ;

Work done under the trapezoid shaped area:

1/2 {a+b} h = 1/2 { 2d + d } F₀

W=3/2dF₀

Work done on the triangle shaped part

W= 1/2 * b * h

W= 1/2 * d * -F₀ = -1/2dF₀

The net work done :

3/2dF₀ -1/2dF₀ = 1dF₀