How would you find the x-intercept of f(x)=(x-4)^2-3?

Question

asked Feb 9, 2018 27.7k views

1 Answer

Nalla Srinivas · Answer 1 · 2018-02-16T00:26:13+0000

The x -intercepts occur when f(x) =0
So,
(x-4)^2 = x^2 -8x + 16 -3 =0
x^2 -8x + 13 =0
Solving by the quadratic formula
x1 = 5.7321
x2 = 2.2679