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The length of a rectangle is 3 inches more than its width. The perimeter of the rectangle is 34 inches. The length of the rectangle is inches, and its width is inches.

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l=3+w
w=w
p=2(3+w)+2w
p=6+2w+2w
p=6+4w
34=6+4w
28=4w
w=7
l=10
User Karrie
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Answer:

The width of rectangle is 7 inches.

The length of rectangle is 10 inches.

Explanation:

Let w represent width and l represent length of the rectangle.

We have been given that the length of a rectangle is 3 inches more than its width. We can represent this information in an equation as:


l=w+3...(1)

We are also told that the perimeter of the rectangle is 34 inches. We know that perimeter of a rectangle is two times its width and length. We can represent this information in an equation as:


2(w+l)=34...(2)

Upon substituting equation (1) in equation (2), we will get:


2(w+w+3)=34


2(2w+3)=34

Using distributive property
a(b+c)=ab+ac, we will get:


2*2w+2*3=34


4w+6=34


4w+6-6=34-6


4w=28


(4w)/(4)=(28)/(4)


w=7

Therefore, the width of rectangle is 7 inches.

Upon substituting
w=7 in equation (1), we will get:


l=w+3


l=7+3


l=10

Therefore, the length of rectangle is 10 inches.

User Zud
by
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