Question

PLEASE HELP (100)

A block M, with mass of 4 kg, is released from rest and slides down a ramp that is angled at 28° above the horizontal (from the bottom of the ramp). The length of the ramp, d, is 3 meters. How much work is done by the gravitational force as the block slides down the ramp?

Answer 1

The work done will be
`W=55.27\: J`

Step-by-step explanation:

The work equation is given by:

`W=F\cdot x`

Where:

F is the force due to gravity (weight = mg)

x is the length of the ramp (3 m)

Now, the force acting here is the component of weight in the ramp direction, so it will be:

`F_(x-direction)=mgsin(28)`

Therefore, the work done will be:

`W=mgsin(28)*3`

`W=4*9.81*sin(28)*3`

`W=55.27\: J`

I hope it helps you!