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Given that bisects ∠CEA, which statements must be true? Check all that apply. m∠CEA = 90° m∠CEF = m∠CEA + m∠BEF m∠CEB = 2(m∠CEA) m∠BEF = 135° ∠CEF is a straight angle. ∠AEF is a right angle.

User Amartel
by
6.2k points

2 Answers

4 votes
the 1,3,4
that is what i think it might be but i could be wrong
User Yva
by
5.7k points
3 votes

see the attached figure to better understand the problem

we know that

An angle bisector divides the angle into two angles with equal measures

So

m∠CEA=
90°

m∠AEB=m∠BEC=
45°

Statements

case 1) m∠CEA=
90°

Is True

∠CEA is a right angle

case 2) m∠CEF = m∠CEA + m∠BEF

Is False

we know that

m∠CEF=
180° ---> is a straight angle

and

m∠CEA + m∠BEF=
90+135=225°

m∠CEF
\\eq m∠CEA + m∠BEF

case 3) m∠CEB = 2(m∠CEA)

Is False

m∠CEB=
45°

2(m∠CEA)=
2*90=180°

m∠CEB
\\eq 2(m∠CEA)

case 4) m∠BEF = 135°

Is True

m∠BEF=m∠BEA+m∠AEF

m∠BEA=
45°

m∠AEF=
90°

Substitute

m∠BEF=
45+90=135°

case 5) ∠CEF is a straight angle

Is True

m∠CEF=
180°

case 6) ∠AEF is a right angle

Is True

m∠AEF=
90°

therefore

the answers are

m∠CEA=
90°

m∠BEF = 135°

∠CEF is a straight angle

∠AEF is a right angle

Given that bisects ∠CEA, which statements must be true? Check all that apply. m∠CEA-example-1
User Styler
by
6.0k points