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if the solubility of a gas is 705g/L at 404 at kPa pressure, what is the solubility of the gas when the pressure is 202 kPa

User Manie
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1 Answer

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Data:
C1 (initial concentration) = 705 g/L
P1 (initial pressure) = 404 kPa
C2 (final concentration) = ? (g/L)
P2 (final pressure) = 202 kPa

Formula:
P1 * C1 = P2 * C2

Solving:
P1 * C1 = P2 * C2
404 * 705 = 202 * C2
284820 = 202 C2
202 C2 = 284820

C_(2) = (284820)/(202)

\boxed{\boxed{C_(2) = 1410\:g/L}}\end{array}}\qquad\quad\checkmark
User Kevon
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