Question

A 0.100-kilogram apple falls from a height of 1.50 meters to 1.00 meter. Ignoring frictional effects, the total mechanical energy of the apple at this height is

Answer 1

Since the mechanical energy at any point is constant in this case, the total mechanical energy before the apple fell is the same as at any point during its fall. Hence it is simply mgh=0.1×9.8×1.5 = 1.47 J

Answer 2

Mechanical energy = 1.47 J

Step-by-step explanation:

As we know that mechanical energy is the sum of kinetic energy and gravitational potential energy.

Since the apple falls from the height of 1.50 m so here in this case its initial speed must be zero

so initial kinetic energy is given as

`KE = 0`

now its gravitational potential energy is given as

`U = mgh`

now plug in all values in it

`U = (0.100 kg)(9.81 m/s^2)(1.50 m)`

`U = 1.47 J`

so mechanical energy is given as

`ME = 1.47 + 0 = 1.47 J`