52.2k views
2 votes
A dump truck brought 1⁄3 of a ton of rock on the first trip, 1⁄2 of a ton on the second trip, but on the third trip, had to take back 4⁄5 of a ton. What was the total weight of the rock left at the construction site?

User Jmls
by
8.0k points

2 Answers

3 votes

Answer:1/3

Explanation:

1+1+1=3

so the answer is 1/3

User Mike Beckerle
by
8.4k points
2 votes

Answer:

1/30 of a ton

Explanation:

Write this as an expression:

1/3 of a ton and 1/2 of a ton were taken to the site.

4/5 of a ton were remove from the site.

Amount of a ton at the site =
(1)/(3)+ (1)/(2)- (4)/(5)

Solve the equation by finding common denominators (when the bottom numbers are the same).


((1)/(3)+ (1)/(2))- (4)/(5) Focus on the first part. The least common multiple (LCM) of 3 and 2 is "6", which will become the denominator.

For 1/3 to become ?/6, multiply top and bottom by 2.

For 1/2 to become ?/6, multiply top and bottom by 3.


((2)/(6)+ (3)/(6))- (4)/(5)

Now we can add the numerators together over the same denominator.


(5)/(6)- (4)/(5)

Do the same thing as before and change the denominators. The LCM of 6 and 5 is "30".

For 5/6 to become ?/30, multiply top and bottom by 5.

For 4/5 to become ?/30, multiply top and bottom by 6.


(25)/(30)- (24)/(30)

Subtract the numerators:


(1)/(30) Answer in tons

Therefore there was 1/30 of a ton of rock left at the construction site.

User Nadunc
by
7.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories