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A dump truck brought 1⁄3 of a ton of rock on the first trip, 1⁄2 of a ton on the second trip, but on the third trip, had to take back 4⁄5 of a ton. What was the total weight of the rock left at the construction site?

User Jmls
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2 Answers

3 votes

Answer:1/3

Explanation:

1+1+1=3

so the answer is 1/3

User Mike Beckerle
by
8.4k points
2 votes

Answer:

1/30 of a ton

Explanation:

Write this as an expression:

1/3 of a ton and 1/2 of a ton were taken to the site.

4/5 of a ton were remove from the site.

Amount of a ton at the site =
(1)/(3)+ (1)/(2)- (4)/(5)

Solve the equation by finding common denominators (when the bottom numbers are the same).


((1)/(3)+ (1)/(2))- (4)/(5) Focus on the first part. The least common multiple (LCM) of 3 and 2 is "6", which will become the denominator.

For 1/3 to become ?/6, multiply top and bottom by 2.

For 1/2 to become ?/6, multiply top and bottom by 3.


((2)/(6)+ (3)/(6))- (4)/(5)

Now we can add the numerators together over the same denominator.


(5)/(6)- (4)/(5)

Do the same thing as before and change the denominators. The LCM of 6 and 5 is "30".

For 5/6 to become ?/30, multiply top and bottom by 5.

For 4/5 to become ?/30, multiply top and bottom by 6.


(25)/(30)- (24)/(30)

Subtract the numerators:


(1)/(30) Answer in tons

Therefore there was 1/30 of a ton of rock left at the construction site.

User Nadunc
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7.7k points