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Solve the triangle. Round your answers to the nearest tenth.law of sines 9.A. m∠B=43, m∠C=32, b=28B. m∠B=47, m∠C=28, b=24C. m∠B=47, m∠C=28, b=28D. m∠B=46, m∠C=29, b=24

Solve the triangle. Round your answers to the nearest tenth.law of sines 9.A. m∠B-example-1
User Eric Le Fort
by
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1 Answer

27 votes
27 votes

The law of sines is expressed as

a/SinA = b/SinB = c/SinC

Where

a, band c are sides of the triangles

A, B and C are the angles opposite the sides respectively

From the diagram,

A = 105

a = 37

c = 18

C = ?

Thus,

37/Sin105 = 18/SinC

By cross multiplying, it becomes

37SinC = 18Sin105

SinC = 18Sin105/37

SinC = 0.46991

C = arcSin0.46691

m∠C = 28

The sum of the angles in a triangle is 180 degrees. This means that

A + B + C = 180

105 + B + 28 = 180

133 + B = 180

B = 180 - 133 = 47

m∠B = 47

By applyingthe sine rule,

b/Sin47 = 37/Sin105

By cross multiplying, it becomes

bSin105 = 37Sin47

b = 37Sin47/Sin105

b = 28

The correct option is

C. m∠B=47, m∠C=28, b=28

User Vahan Babayan
by
2.7k points
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