Question

A snowboarder leaves an 8-foot tall ramp with an upward velocity of 28 feet per second. The function h =− 16t 8t gives the height h (in 2 + 2 + 8 feet) of the snowboarder after t seconds. When does the snowboarder hit the ground?

Answer 1

2 seconds

Explanation:

Given that:

h = -16t² + 28t + 8

Using quadratic formula:

`(-b \pm √(b^2 - 4ac))/(2a)`

where;

a = -16

b = +28

c = +8

`= (-(28) \pm √((28)^2 - 4(-16)(8)))/(2(-16))`

`= \frac{-(28) \pm √(784+512)} {-32}`

`= \frac{-(28) + √(784+512)} {-32} \ \ OR \ \ = \frac{-(28) - √(784+512)} {-32}`

`=- (1)/(4) \ \ OR \ \ 2`

Since we are considering the positive value; Then it will take the snowboarder 2 seconds before it hits the ground.