Question

A milk tank at a dairy farm has the form of a rectangular prism. The tank is 3.5 feet wide. The width of the tank is 5/7 of its length, and the height is 4/5 of its width. How many cubic feet of milk can the tank hold? How many pounds of milk can it hold if 1 cubic foot of milk weighs 66.5 lbs?

Answer 1

The tank can hold 47.78 cubic feet or 3177.61 pounds of milk, by calculating the tank's dimensions and using the weight per cubic foot of milk.

Step-by-step explanation:

The question involves finding the volume of milk a tank can hold and then converting that volume into weight. Given that the tank is a rectangular prism with a width of 3.5 feet, and the width is 5/7 of its length, we first find the length of the tank by setting up the proportion:

Width = (5/7) × Length

3.5 = (5/7) × Length

Length = 3.5 × (7/5) = 4.9 feet

Next, since the height is 4/5 of the width, we calculate the height:

Height = (4/5) × 3.5 = 2.8 feet

We then find the volume of the tank by multiplying the dimensions together:

• Volume = Length × Width × Height = 4.9 × 3.5 × 2.8 = 47.78 cubic feet

To find the weight of milk the tank can hold, we multiply the volume by the weight of milk per cubic foot:

• Weight of milk = Volume × Weight per cubic foot = 47.78 × 66.5 = 3177.61 pounds

The tank can hold 47.78 cubic feet or 3177.61 pounds of milk.

Answer 2

48.02 or 48 1/50 cubic feet and 3193.33 or 3193 33/100 LB ( I do rsm too )

Step-by-step explanation:

The width is 3.5

The length is 3.5*7/5 which is 4.9

The height is 4/5 of 3.5 which is 2.8

So, the volume in cubic feet is 3.5*4.9*2.8 which is 48.02 or 48 1/50

So, the amount in Lb is 66.5*48.02 which is 3193.33 or 3193 33/100