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4 votes
Solve for "z".

a(t+z)=45z+67

2 Answers

4 votes

Answer:

Because z is the unknown that we need to find, we treat t and a as constants (or numbers).

a(t+z)= 45z+67

⇒ at+ az= 45z+ 67 (distributive property)

⇒ at- 67= 45z- az

⇒ at- 67= z(45- a) (distributive property)

⇒ (at -67)/ (45- a)= z

Final answer: z= (at- 67)/ (45- a)

User Fortyrunner
by
8.0k points
3 votes
Because z is the unknown that we need to find, we treat t and a as constants (or numbers).

a(t+z)= 45z+67
⇒ at+ az= 45z+ 67 (distributive property)
⇒ at- 67= 45z- az
⇒ at- 67= z(45- a) (distributive property)
⇒ (at -67)/ (45- a)= z

Final answer: z= (at- 67)/ (45- a)

Hope this helps.
User Macks
by
8.1k points

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