Question

What is the length of the line segment with endpoints (−3,8) and (7, 8) ? Enter your answer in the box

Answer 1

Length = √(y2-y1)² + (x2-x1)²
l = √(8-8)² + (7+3)²
l = √10²
l = 10

In short, Your Answer would be 10 units

Hope this helps!

Answer 2

10 units

Explanation:

`(x_1,y_1)=(-3,8)`

`(x_2,y_2)= (7, 8)`

We are supposed to find the length of the line segment with endpoints (−3,8) and (7, 8)

We will use distance formula :
`d=√((x_2-x_1)^2+(y_2-y_1)^2)`

Substitute the values :

`d=√((7+3)^2+(8-8)^2)`

`d=√(100)`

`d=10`

Hence the length of the line segment with endpoints (−3,8) and (7, 8) is 10 units