7.4k views
1 vote
There are the same remainder 3 when 135, 111, 87, is divided by a certain number. Find the largest possible value of this number

yowwww plssss answer quickly the submission is tommorow ​

User Jglstewart
by
2.9k points

1 Answer

9 votes

Answer:

  • 12

Explanation:

Below numbers are divisible by the number we are looking for:

  • 135 - 3 = 132
  • 111 - 3 = 108
  • 87 - 3 = 84

Lets find GCF of the three numbers:

  • 132 = 11*2*2*3
  • 108 = 2*2*3*3*3
  • 84 = 7*2*2*3

GCF(132, 108, 84) = 2*2*3 = 12

The largest possible number is 12

User Macs Dickinson
by
3.3k points