7.4k views
1 vote
There are the same remainder 3 when 135, 111, 87, is divided by a certain number. Find the largest possible value of this number

yowwww plssss answer quickly the submission is tommorow ​

User Jglstewart
by
7.9k points

1 Answer

9 votes

Answer:

  • 12

Explanation:

Below numbers are divisible by the number we are looking for:

  • 135 - 3 = 132
  • 111 - 3 = 108
  • 87 - 3 = 84

Lets find GCF of the three numbers:

  • 132 = 11*2*2*3
  • 108 = 2*2*3*3*3
  • 84 = 7*2*2*3

GCF(132, 108, 84) = 2*2*3 = 12

The largest possible number is 12

User Macs Dickinson
by
8.2k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories