Question

If the mass of a system is halved (m’=m/2) and the net force acting on it is doubled (F’=2F), then its acceleration would be:* 7 points unchanged (x1) halved (x0.5) quartered (x0.25) doubled (x2) quadrupled (x4)

Answer 1

Given:

The mass of the system is m' =m/2

The net force acting on it is F' = 2F

To find the acceleration.

Step-by-step explanation:

The acceleration will be

`\begin{gathered} a^(\prime)=(F^(\prime))/(m^(\prime)) \\ =(2F)/((m)/(2)) \\ =(4F)/(m) \\ a^(\prime)=4a \end{gathered}`

Thus, the acceleration would be quadrupled(x4).