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Attached is the problem, if anyone could help me and explain this I would be grateful.

Attached is the problem, if anyone could help me and explain this I would be grateful-example-1

1 Answer

4 votes
let's say that, that equals some angle θ
thus
\bf sec^(-1)(1)=\theta \iff sec(\theta)=1\\\\ -----------------------------\\\\ sec(\theta)=\cfrac{1}{cos(\theta)}\qquad thus\\\\ -----------------------------\\\\ \cfrac{1}{cos(\theta)}=1\implies \cfrac{1}{1}=cos(\theta)\implies 1=cos(\theta) \\\\\\ \textit{now, taking }cos^(-1)\textit{ to both sides} \\\\\\ cos^(-1)(1)=\theta

so.. .check your Unit Circle, what is that angle anyway?
User Enrique Saez
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