Question

This probability distribution shows thetypical grade distribution for a Geometrycourse with 35 students.GradeEnter a decimal rounded to the nearest hundredth.Enter

Answer 1

Step-by-step explanation:

The total number of students is

`n(S)=35`

Concept:

To figure out the probability that a student earns grade A,B or C

Will be calculated below as

`P(A,BorC)=P(A)+P(B)+P(C)`

The Probability of A is

`P(A)=(n(A))/(n(S))=(5)/(35)`

The probabaility of B is

`P(B)=(n(B))/(n(S))=(10)/(35)`

The probabaility of C is

`P(B)=(n(B))/(n(S))=(15)/(35)`

Hence,

By substituting the values in the concept, we will have

`\begin{gathered} P(A,BorC)=P(A)+P(B)+P(C) \\ P(A,BorC)=(5)/(35)+(10)/(35)+(15)/(35)=(30)/(35) \\ P(A,BorC)=0.857 \\ P(A,BorC)\approx0.86(nearest\text{ }hundredth) \end{gathered}`

Hence,

The final answer is

`0.86`