222k views
14 votes
Solve for p and q if
p+q=2(p-q)
pq=675​

User Ian M
by
8.3k points

2 Answers

5 votes

Step-by-step explanation:-

Let p + q = 2( p - q) be eqn.1 and pq = 675 be eqn.2

Now , lets expand eqn.1


=> p + q = 2p - 2q


=> 2p - p = 2q + q


=> p = 3q

Lets put the value of p in eqn.2


=> 3q * q = 675


=> 3q^(2) = 675


=> q^(2) = (675)/(3) = 225


=> q = √(225) = +15 \: or \: -15

Lets find out the value of p.

When q = +15 ,
p = 3 * 15 = 45

When q = -15 ,
p = 3 * - 15 = -45

Hence ,

p = ±45

q = ±15

User MYnDstrEAm
by
8.2k points
8 votes

Answer:

q=15

p=45

Explanation:

p+q=2(p-q)

p+q=2p-2q

simplify: add 2q to each side and subtract one p from each side of the equation.

p=3q

given that pq=675, substitute:

(3q)q=675

3q^2=675

q^2=225

q=15

then p=3q or p=3(15)=45

p=45

User Mfoo
by
7.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories