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5 votes
Which of the following lines has a slope of -1/2?

x + 2y = 0
x - 2y = 0
-x + 2y = 0
y = x - 1/2

User Rawr Rang
by
8.5k points

2 Answers

2 votes

Answer:

A.) x + 2y = 0

Explanation:

User Kamui
by
7.9k points
5 votes

Answer-


\mathbf{x + 2y = 0} has a slope of
-(1)/(2)

Solution-

The general point slope formula of straight line,


y=mx+c

Where,

m = slope

c = y-intercept


\mathbf{x + 2y = 0}


\Rightarrow y=-(x)/(2)

Comparing with general equation, slope =
-(1)/(2)


\mathbf{x - 2y = 0}


\Rightarrow y=(x)/(2)

Comparing with general equation, slope =
(1)/(2)


\mathbf{-x + 2y = 0}


\Rightarrow y=(x)/(2)

Comparing with general equation, slope =
(1)/(2)


\mathbf{y = x -(1)/(2)}

Comparing with general equation, slope = 1, y-intercept =
-(1)/(2)

Therefore,
\mathbf{x + 2y = 0} has a slope of
-(1)/(2)


User Bhavna
by
7.6k points

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