Question

Which of the following lines has a slope of -1/2?

x + 2y = 0
x - 2y = 0
-x + 2y = 0
y = x - 1/2

Answer 1

A.) x + 2y = 0

Explanation:

Answer 2

`\mathbf{x + 2y = 0}` has a slope of
`-(1)/(2)`

Solution-

The general point slope formula of straight line,

`y=mx+c`

Where,

m = slope

c = y-intercept

`\mathbf{x + 2y = 0}`

`\Rightarrow y=-(x)/(2)`

Comparing with general equation, slope =
`-(1)/(2)`

`\mathbf{x - 2y = 0}`

`\Rightarrow y=(x)/(2)`

Comparing with general equation, slope =
`(1)/(2)`

`\mathbf{-x + 2y = 0}`

`\Rightarrow y=(x)/(2)`

Comparing with general equation, slope =
`(1)/(2)`

`\mathbf{y = x -(1)/(2)}`

Comparing with general equation, slope = 1, y-intercept =
`-(1)/(2)`

Therefore,
`\mathbf{x + 2y = 0}` has a slope of
`-(1)/(2)`