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B2O3(s) + 3C(s) + 3Cl2 (g) ---> 2 BCl3(g) + 3CO(g) Calculate how many moles of BCl3 are produced from the reaction of 61.0g of B203? A. 1.75 mol B. 0.0150 mol C. 51.3 mol D. 211 mol
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B2O3(s) + 3C(s) + 3Cl2 (g) ---> 2 BCl3(g) + 3CO(g)

Calculate how many moles of BCl3 are produced from the reaction of 61.0g of B203?
A. 1.75 mol
B. 0.0150 mol
C. 51.3 mol
D. 211 mol

User Kevchadders
by
7.9k points

1 Answer

3 votes
C. 51.3 mol is the answer 
User Noncom
by
8.3k points
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