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How many grams of P2O5 can be produced from 4.6 x 1023 atoms of P?

User Theressa
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\\ \tt\longmapsto No\:of\:moles=(No\:of\:atoms)/(Avagadro's\:no)


\\ \tt\longmapsto No\:of\: moles=(4.6* 10^(23))/(6.022* 10^(23))


\\ \tt\longmapsto No\:of\:moles=0.76=0.8mol

Now


\\ \tt\longmapsto Given\:mass=No\:of\:moles(Molar\:mass)


\\ \tt\longmapsto Given\:mass=0.8(284)


\\ \tt\longmapsto Given\:mass=227.2g

User Vikram Pudi
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