Given:
Selling price of a fan = Rs.4700
Loss percent = 6%
To find:
The price at which he must sell it to gain 6 percentage.
Solution:
Let x be the cost price of the fan.
Loss percent = 6%
Selling price = Cost price - 6% of cost price
![S.P.=x-(6)/(100)x](https://img.qammunity.org/2022/formulas/mathematics/college/cba2fasohilt7220o1vbqlo6oyywkop0rc.png)
![S.P.=x-0.06x](https://img.qammunity.org/2022/formulas/mathematics/college/5rrsekgakm7wo57j1ecg6p4fjlhokhw5eg.png)
![S.P.=0.94x](https://img.qammunity.org/2022/formulas/mathematics/college/p6wco4p80s122vonj3ucxe81nk7ow99bms.png)
Selling price of a fan = Rs.4700
![4700=0.94x](https://img.qammunity.org/2022/formulas/mathematics/college/vw7lprzf1pw7to3uzsds3mrqu2fuwz2hnd.png)
![(4700)/(0.94)=x](https://img.qammunity.org/2022/formulas/mathematics/college/vjmhndrfx60nvfd1mmnwbfzjnmcjtd33tq.png)
![5000=x](https://img.qammunity.org/2022/formulas/mathematics/college/viezgas1r47ug9z2u6io6v0ykj3unjx3dz.png)
So, the cost price of the fan is Rs.5000.
Now, he need to sell this fan in 6% gain.
Selling price = Cost price + 6% of cost price
![S.P.=5000+(6)/(100)* 5000](https://img.qammunity.org/2022/formulas/mathematics/college/3gj3pox3hgcso8yqda3dgpdz7okhajaxbt.png)
![S.P.=5000+300](https://img.qammunity.org/2022/formulas/mathematics/college/i8djb1kys0zenxm2j5xchcrynvx6abjy1w.png)
![S.P.=5300](https://img.qammunity.org/2022/formulas/mathematics/college/zlcvfa6g8xzyudjvywihr4bsu4d7uiu1dg.png)
Therefore, he must sell it for Rs.5300 to gain 6 percentage.