Question

What is the temperature in kelvin of a gas if it is allowed to expand from 1.50 L to 4.50 L? The initial temperature is 10.0°C and pressure is constant throughout the change. Which equation should you use?

Answer 1

Answer: Equation: T2 = V2/V1 T1

Final temperature: 849 K

Step-by-step explanation:

Answer 2

Answer: 1) 849 K

2)
`(V_1)/(T_1)=(V_2)/(T_2)`

Step-by-step explanation:

Charles' Law: This law states that volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

`V\propto T` (At constant pressure and number of moles)

`(V_1)/(T_1)=(V_2)/(T_2)`

`V_1`= initial volume = 1.50 L

`V_2`= final volume = 4.50 L

`T_1`= initial temperature =
`10^0C=(10+273)K=283K`

`T_2`= final temperature =?

`(1.50 )/(283)=(4.50)/(T_2)`

`T_2=849K`